Wrong!
Also Phantera calculations might mislead you,
the kettle might have a power of 2kW (not kWh) but it won't consume 2kWh of energy but only for (say) the 3 minutes needed to boil the water so it would use only 2*3/60=0,1kWh of energy.
Also in the washer, the heater might be 2,7kW powerful but, unless doing a boilwash with a gigantic amount of water, it will use a fraction of that.
The dryer will, istead most likely use more than the 3,2kWh to dry a load, it's all a matter of how long the heating element is on during the cycle.
Your dishwasher will use 1,05kWh in total, as I said before:
here is an example of a theoric cyle
10 minutes prewash
45 minutes main wash
5 minutes cold rinse
60 minutes hot rinse and dry
the motor runs all the time for 2 hours
in the prewash the heater is off
the heater brings the temperature of main wash to 50°C in 9 minutes
in the first rinse the heater is off
in the last rinse the heater brings the water to 65°C 11 minutes
so in total the heater runs for 20 minutes
with a motor power of 200W (0,2kW) and heater power of 2000 (2kW) you have:
power x time = energy
0,2 kW x 2 hours = 0,4 kWh
2 kW x 20 minutes ( 1/3 h) = 0,66 kWh
so in total said dishwasher would use 1,06kWh of energy in the complete cycle.
I hope this explains it nicely
