funktionalart
Well-known member
Hi All,
Recently, I purchased a fantastic early 60s custom home. If you're super astute, or a fan of vintage design magazines, you may recognise the door details from a feature in 1963 House Beautiful--the place is a design by Loch Crane (famed San Diego architect and Frank Lloyd Wright pupil).
I Am slowly going through the place taking notes on all the projects I need to complete. My front entry door (which is actually in the garage/carport) has a Baldwin-style mortise lockset. I'm not sure who made it (Could be Yale or Sargent?).
Because the door is basically functional and because you can have problems if you remove this stuff the wrong way, I do NOT want to remove the mortise assembly yet.
I know that doing so is vital to verify size/mfg., but the lockset has NOT got a knob on the exterior side. So, I'm not even sure if it's a 2-1/2" or 2-3/4" setback. What I would like to know, before I do any removals, is what I might need to determine in order to just fit a front knob (or thumblatch type?). My preference is to do that vs. replacing everything with brand new lockset and knobs.
As of now, I can open/close it with no issues (from inside the house), and always leave it "off the latch" using the push buttons when I go outside--leaving a cardboard wedge to keep door from blowing open when I'm outside. Obviously, I'd really like to be able to fit a proper exterior doorknob, and for now anyway, would prefer not to replace the whole assembly unless I absolutely have to. The exterior face or the door is covered in decorative panels (See pic--I have all the missing ones in a box). Because I want to retain the original panels, there is precious little room to fit certain styles of knobs and/or trim plates, etc. I *could* do so and just leave one panel out, but it's gonna look odd that way...




Recently, I purchased a fantastic early 60s custom home. If you're super astute, or a fan of vintage design magazines, you may recognise the door details from a feature in 1963 House Beautiful--the place is a design by Loch Crane (famed San Diego architect and Frank Lloyd Wright pupil).
I Am slowly going through the place taking notes on all the projects I need to complete. My front entry door (which is actually in the garage/carport) has a Baldwin-style mortise lockset. I'm not sure who made it (Could be Yale or Sargent?).
Because the door is basically functional and because you can have problems if you remove this stuff the wrong way, I do NOT want to remove the mortise assembly yet.
I know that doing so is vital to verify size/mfg., but the lockset has NOT got a knob on the exterior side. So, I'm not even sure if it's a 2-1/2" or 2-3/4" setback. What I would like to know, before I do any removals, is what I might need to determine in order to just fit a front knob (or thumblatch type?). My preference is to do that vs. replacing everything with brand new lockset and knobs.
As of now, I can open/close it with no issues (from inside the house), and always leave it "off the latch" using the push buttons when I go outside--leaving a cardboard wedge to keep door from blowing open when I'm outside. Obviously, I'd really like to be able to fit a proper exterior doorknob, and for now anyway, would prefer not to replace the whole assembly unless I absolutely have to. The exterior face or the door is covered in decorative panels (See pic--I have all the missing ones in a box). Because I want to retain the original panels, there is precious little room to fit certain styles of knobs and/or trim plates, etc. I *could* do so and just leave one panel out, but it's gonna look odd that way...



